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[3915] The Ordinal Number Function

• • Reply

  9 years ago

  by Developer Fusion Bot

  Developer Fusion Bot

  , United Kingdom

  Joined 2 years ago

  This thread is for discussions of The Ordinal Number Function.

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• • Reply

  4 years ago

  by basicgeoff

  basicgeoff

  , United States

  Joined 4 years ago

  public string GetOrdinal(int Number)
  {
     //Adapted from VB.NET version posted at http://www.developerfusion.com/show/3915/
     //The Ordinal Number Function
     //Karl Moore - http://www.karlmoore.com
  

  
     string suffix = String.Empty;
     // Accepts an integer, returns the ordinal suffix
     // Handles special case three digit numbers ending
     // with 11, 12 or 13 - ie, 111th, 112th, 113th, 211th, et al
     if(Number.ToString().Length > 2)
     {
         int intEndNum = Convert.ToInt32(Number.ToString().Substring(Number.ToString().Length - 2,2));
         if(intEndNum >=11 && intEndNum <= 13)
             switch(intEndNum)
             {
                 case 11:
                 case 12:
                 case 13:
                     suffix = "th";
                     break;
             }
     }
  

  
     if(Number >= 21)
     {
         //Handles 21st, 22nd, 23rd, et al
         int Number21 = Convert.ToInt32(Number.ToString().Substring(Number.ToString().Length -1,1));
         switch(Number21)
         {
             case 1:
                 suffix = "st";
                 break;
             case 2:
                 suffix = "nd";
                 break;
             case 3:
                 suffix = "rd";
                 break;
             case 0:
                 suffix = "th";
                 break;
             default:
                 for(int i = 4;i<=9;i++)
                 {
                     if(Number21 == i)
                     {
                         suffix = "th";
                         break;
                     }
                     else
                         suffix = String.Empty;
                 }
                 break;
         }
     }
     else
     {
         switch(Number)
         {
             case 1:
                 suffix = "st";
                 break;
             case 2:
                 suffix = "nd";
                 break;
             case 3:
                 suffix = "rd";
                 break;
             default:
                 for(int i = 4;i<=21;i++)
                 {
                     if(Number == i)
                     {
                         suffix = "th";
                         break;
                     }
                     else
                         suffix = String.Empty;
                 }
                 break;
         }
     }
  

  
     return suffix;
  }

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• • Reply

  3 years ago

  by ianw

  ianw

  , United States

  Joined 3 years ago

  Here's a shorter version (that also returns 'th' for zero):
  

  
  

  Code:

  
     Private Function GetOrdinal2(ByVal Number As Integer) As String
  

  
         If ((Number Mod 100) \ 10) <> 1 Then
             If (Number Mod 10) = 1 Then
                 Return "st"
             ElseIf (Number Mod 10) = 2 Then
                 Return "nd"
             ElseIf (Number Mod 10) = 3 Then
                 Return "rd"
             Else
                 Return "th"
             End If
         Else
             Return "th"
         End If
  

  
     End Function
  

  
  

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• • Reply

  2 years ago

  by jenisys

  John Nowak

  , United States

  Joined 2 years ago

  First, thanks for already doing what I was about to do -- creating a C# version.
  

  
  In the C# version, you added a separate if for 21st, 22nd, 23rd.  Is there a reason?  It seems the code for 1st, 2nd, and 3rd would work just as well for 21st, 22nd , or 23rd.
  

  
  Just curious.
  

  
  

  Quote:

  [1]Posted by basicgeoff on 29 Dec 2003 01:24 PM[/1]
  public string GetOrdinal(int Number)
  {
     //Adapted from VB.NET version posted at http://www.developerfusion.com/show/3915/
     //The Ordinal Number Function
     //Karl Moore - http://www.karlmoore.com
  

  
     string suffix = String.Empty;
     // Accepts an integer, returns the ordinal suffix
     // Handles special case three digit numbers ending
     // with 11, 12 or 13 - ie, 111th, 112th, 113th, 211th, et al
     if(Number.ToString().Length > 2)
     {
         int intEndNum = Convert.ToInt32(Number.ToString().Substring(Number.ToString().Length - 2,2));
         if(intEndNum >=11 && intEndNum <= 13)
             switch(intEndNum)
             {
                 case 11:
                 case 12:
                 case 13:
                     suffix = "th";
                     break;
             }
     }
  

  
     if(Number >= 21)
     {
         //Handles 21st, 22nd, 23rd, et al
         int Number21 = Convert.ToInt32(Number.ToString().Substring(Number.ToString().Length -1,1));
         switch(Number21)
         {
             case 1:
                 suffix = "st";
                 break;
             case 2:
                 suffix = "nd";
                 break;
             case 3:
                 suffix = "rd";
                 break;
             case 0:
                 suffix = "th";
                 break;
             default:
                 for(int i = 4;i<=9;i++)
                 {
                     if(Number21 == i)
                     {
                         suffix = "th";
                         break;
                     }
                     else
                         suffix = String.Empty;
                 }
                 break;
         }
     }
     else
     {
         switch(Number)
         {
             case 1:
                 suffix = "st";
                 break;
             case 2:
                 suffix = "nd";
                 break;
             case 3:
                 suffix = "rd";
                 break;
             default:
                 for(int i = 4;i<=21;i++)
                 {
                     if(Number == i)
                     {
                         suffix = "th";
                         break;
                     }
                     else
                         suffix = String.Empty;
                 }
                 break;
         }
     }
  

  
     return suffix;
  }
  

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• • Reply

  1 year ago

  by CMercs

  Cyber Mercenary

  , United States

  Joined 1 year ago

  Here is a shorter C# version;

  /// <summary>
  /// Method to properly suffix numbers with "st", "nd", "rd" or "th".
  /// </summary>
  /// <param name="iNumber">Number to add the suffix to.</param>
  /// <returns>Number as a properly suffixed string (i.e. 1st, 2nd, 3rd, 4th, 11th, 21st, etc.)</returns>
  /// <example><code>
  /// for (int i = 1; i &lt; 1305; i++)
  /// {
  ///     Console.WriteLine(Utility.GetOrdinal(i));
  /// }
  /// </code></example>
  public static string GetOrdinal(int iNumber)
  {
     string suf = "th";
     if (((iNumber % 100) / 10) != 1) //Handles 11, 12 & 13.  Only equals one if iNumber has a one in the ten digit.
     {
        switch (iNumber % 10) //Returns digit in the 1 column to evaluate.
        {
           case 1:
              suf = "st";
              break;
           case 2:
              suf = "nd";
              break;
           case 3:
              suf = "rd";
              break;
        }
     }
     return iNumber.ToString() + suf;
  }
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  

   

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